9.1.7 Checkerboard V2 Codehs !!better!! Jun 2026

for (var row = 0; row < GRID_SIZE; row++) for (var col = 0; col < GRID_SIZE; col++) // Drawing logic goes here Use code with caution. 3. Applying Conditional Logic

is a common way to format the output so it looks like a clean grid in the console. Example Code Snippet The following logic illustrates how to construct the grid correctly: # 1. Initialize the board # 2. Outer loop for rows # 3. Inner loop for columns # 4. Check for even/odd sum : row.append( : row.append( ) board.append(row) # 5. Print the formatted board board: print .join([str(x) Use code with caution. Copied to clipboard Why version 2 is different

// Draw the checkerboard for (var row = 0; row < 8; row++) for (var col = 0; col < 8; col++) // Calculate the top-left corner of this square var x = col * SQUARE_SIZE; var y = row * SQUARE_SIZE;

This happens if you try to access board[8] or board[row][8] . Remember that for an 8x8 board, indices are Alternative Approach: Alternating Rows 9.1.7 Checkerboard V2 Codehs

: Ensure your range() parameters correctly cover indices 0 through 7 for an 8x8 board.

Inside the nested loop, use the (row + col) % 2 logic to assign 1 to the correct positions using the syntax grid[row][col] = 1 .

What or specific CodeHS template are you using? (Java, JavaScript, Karel?) for (var row = 0; row is a

If you are looking for assistance with next steps in your curriculum,1.8 (Checkerboard V3) or so I can prepare the correct matrix traversal frameworks for you! Share public link

# This is the logic for the checkerboard pattern: # If the sum of the row and column indices is even, make it red. # Otherwise, make it black. if (row + col) % 2 == 0: pen.color("red") else: pen.color("black")

Happy coding! 🧩

Source: Inspired by common patterns, similar solutions can be found in public Q&A forums.

The goal is typically to draw an 8x8 checkerboard with alternating black and red squares (or another color pair).

If (row + column) % 2 == 0 → Color A. If (row + column) % 2 == 1 → Color B. Outer loop for rows # 3

: Create an empty list and use a loop to append eight rows, each initially filled with eight zeros.